What should be subtracted from 19 28 55 91 so the numbers are in same proportion?

Correct Answer - Option 3 : 28

Given: 

When x is subtracted from each of 19, 28, 55, 91, obtained numbers are in proportion.

Concept used: 

by componendo and dividendo 

(a/b) = (x/y)

⇒ {(a + b)/(a - b)} = {(x + y)/(x - y)}

The mean proportion of x and y is √xy

Solution: 

Given numbers are 19, 28, 55, 91

Accordingly, (19 - x), (28 - x), (55 - x) and (91 - x) are propertional

⇒ {(19 - x)/(28 - x)} = {(55 - x)/(91 - x)

Appling Componendo-Dividendo method get,

{(47 - 2x)/(- 9)} = {(146 - 2x)/(- 36)}

⇒ 188 - 8x = 146 - 2x

⇒ 6x = 42

⇒ x = 7

⇒ mean proportional = √{7 + 9) × 72} = 28

∴ Required mean proportion is 28.


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Updated On: 27-06-2022

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जब x को 19, 28, 55 और 91 में से प्रत्येक से घटाया जाता है, तो इस क्रम में प्राप्त संख्याएं समानुपात में होती हैं। x का मान ज्ञात करें।

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28, 39,72, 105 में से क्या घटाया जाए कि ये समानुपाती हो जाएँ।

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When x is subtracted from each of 19, 28, 55 and 91, the numbers so obtained in this order are in proportion . What is the mean proportion between (x + 9) and `x^2`? जब x को 19, 28, 55 और 91 में से घटाया जाता है, तो इस क्रम में प्राप्त संख्याएँ अनुपात में होती हैं। (x + 9) और `x^2` के बीच माध्य अनुपात क्या है?

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What must be subtracted from `-1` to get `-19` ?

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What number must be subtracted from each of the numbers 10, 12, 19, 24 to get the numbers which are in proportion ?

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21, 38, 55, 106 प्रत्येक में से क्या घटाया जाए कि नई संख्याएँ समानुपाती हों?

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What should be subtracted from 19 28 55 91 so the numbers are in same proportion?

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What should be subtracted so that 19/28 55 91 are in proportion?

When x is subtracted from each of 19, 28, 55, 91, obtained numbers are in proportion. ∴ Required mean proportion is 28.

What number is subtracted from each 21 38 55 and 106 that the new numbers are in the proportional?

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