In how many ways can 8 books be arranged on a shelf if 3 particular books must always stand together
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How many ways can 9 books be arranged in a shelf if two of them must be side by side each other?We know that the two books that are kept together can be arranged in two ways. So, we will get the total number of ways we can arrange the $9$ books. Hence, we can arrange the $9$ on a shelf in $40320\times 2=80640$ ways.
How many ways can 3 books be arranged on a shelf?different bundles of novels, and we have to put this bundle and other 3 books onto the shelf. So the total number of ways is 3! × (3 + 1)! = 144.
How many different orders can 7 books be arranged on a shelf if a certain 3 volume book is not to be separated?If a certain 3 volume work is not to be separated, will be 3 factorial times 5 factorial, and that is 720 repoint.
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