Đề bài
Thực hiện phép chia:
a] \[[6x - 3]:3\] ;
b] \[[4{x^2} - 6x]:2x\] ;
c] \[[15{x^3} + 10{x^2}]:5x\] ;
d] \[[3{x^3} - 9{x^2} + 6x]:3x\] ;
e] \[[14{x^4} + 21{x^3} - 7{x^5}]:7{x^3}\] ;
f] \[[12{x^2}{y^3} - 15{x^4}{y^3} + 9{x^2}{y^2}]:3{x^2}y\] .
Lời giải chi tiết
\[\eqalign{ & a]\,\,\left[ {6x - 3} \right]:3 = {{6x} \over 3} - {3 \over 3} = 2x - 1 \cr & b]\,\,\left[ {4{x^2} - 6x} \right]:\left[ {2x} \right] = {{4{x^2}} \over {2x}} - {{6x} \over {2x}} = 2x - 3 \cr & c]\,\,\left[ {15{x^3} + 10{x^2}} \right]:\left[ {5x} \right] = {{15{x^3}} \over {5x}} + {{10{x^2}} \over {5x}} = 3{x^2} + 2x \cr & d]\,\,\left[ {3{x^3} - 9{x^2} + 6x} \right]:\left[ {3x} \right] = {{3{x^3}} \over {3x}} - {{9{x^2}} \over {3x}} + {{6x} \over {3x}} = {x^2} - 3x + 2 \cr & e]\,\,\left[ {14{x^4} + 21{x^3} - 7{x^5}} \right]:\left[ {7{x^3}} \right] = {{14{x^4}} \over {7{x^3}}} + {{21{x^3}} \over {7{x^3}}} - {{7{x^5}} \over {7{x^3}}} = 2x + 3 - {x^2} \cr & f]\,\,\left[ {12{x^2}{y^3} - 15{x^4}{y^3} + 9{x^2}{y^2}} \right]:\left[ {3{x^2}y} \right] = {{12{x^2}{y^3}} \over {3{x^2}y}} - {{15{x^4}{y^3}} \over {3{x^2}y}} + {{9{x^2}{y^2}} \over {3{x^2}y}} = 4{y^2} - 5{x^2}{y^2} + 3y \cr} \]