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Simplifying
tanx2 + -2tanx + -3 = 0 Reorder the terms:
-3 + -2antx + antx2 = 0 Solving
-3 + -2antx + antx2 = 0 Solving for variable 'a'. Move all terms containing a to the left, all other terms to the right. Add '3' to each side of the equation.
-3 + -2antx + 3 + antx2 = 0 + 3 Reorder the terms:
-3 + 3 + -2antx + antx2 = 0 + 3 Combine like terms: -3 + 3 = 0
0 + -2antx + antx2 = 0 + 3
-2antx + antx2 = 0 + 3 Combine like terms: 0 + 3 = 3
-2antx + antx2 = 3 Reorder the terms:
-3 + -2antx + antx2 = 3 + -3 Combine like terms: 3 + -3 = 0
-3 + -2antx + antx2 = 0
The solution to this equation could not be determined.
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3x + 2 = 18 3x = 18 - 2 3x = 16 [divide both sides by 3 to get x] 3x/3 = 16/3 x = 5.333
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3x = 12 3x = 12 [divide both sides by 3 to get x] 3x/3 = 12/3 x = 4
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| 6x-2=14 | | 2x+10=12 | | 3x+2=18 |
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4x - 2 = 12 4x = 12 + 2 4x = 14 [divide both sides by 4 to get x] 4x/4 = 14/4 x = 3.5
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| 6x-2=14 | | 2x+10=12 | | 3x+2=18 |
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2x + 10 = 12 2x = 12 - 10 2x = 2 [divide both sides by 2 to get x] 2x/2 = 2/2 x = 1
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| 3x+2=18 |
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12 + x = 5 x = 5 - 12 x = -7
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| 4x-2=12 | | 6x-2=14 | | 2x+10=12 | | 3x+2=18 |
Phương trình ${{\tan }^{2}}x-2\tan x-3=0$ có nghiệm là
A.
$\left[ \begin{array}{l}x=-\frac{\pi }{4}+k\pi \\x=\arctan 3+k\pi \end{array} \right.,k\in Z.$
B.
$x=\frac{\pi }{4}+k\pi ,k\in Z.$
C.
D.