Convert list to array python without numpy

I can use this code to check if a row in a matrix = x:

q = [[1,2,1],[1,2,1],[2,1,2]] answer = [sum[row] for row in q] for i in range[0, len[q]]: if answer[i] == 6: print "Player 2 won!" if answer[i] == 3: print "Player 1 won!" if answer[i] != 6 and 3: print "It's a tie!"

How can I check if my matrix has a diagonal or column that = x, without using Numpy [Is there a mathematical way to do it as shown above?]

Example: [X = something that doesn't matter]

q = [[1,X,X],[1,X,X],[1,X,X]] Should print True

q = [[1,X,X],[X,1,X],[X,X,1]] Should print True [Diagonal]

q = [[X,X,1],[X,1,X],[1,X,X]] Should print True [Diagonal{Other One}]

q = [[1,X,X],[X,1,X],[X,1,X]] Should print False

q = [[X,1,X],[X,1,X],[X,1,X]] Should print True [Horizontal]

How the matrix should have its "winning conditions"